2w^2/4w+9=0

Solution for 2w^2/4w+9=0 equation:

2w^2/4w+9=0


Domain of the equation: 4w!=0

w!=0/4

w!=0

w∈R


We multiply all the terms by the denominator


2w^2+9*4w=0

Wy multiply elements

2w^2+36w=0

a = 2; b = 36; c = 0;
Δ = b2-4ac
Δ = 362-4·2·0
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-36}{2*2}=\frac{-72}{4}
=-18
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+36}{2*2}=\frac{0}{4}
=0
$